IP Subnetting - Answers

Answers of previous IP subnetting test :

1.) 55.110.67.205 /16

1. Find the Subnet = 55.110.0.0
2. Find the 1st Usable Host = 55.110.0.1
3. Find the Last Usable Host = 55.110.255.254
4. Find the Broadcast Address = 55.110.255.255

2.) 88.248.235.250 255.255.255.248

1. Find the Subnet = 88.248.235.248
2. Find the 1st Usable Host = 88.248.235.249
3. Find the Last Usable Host = 88.248.235.254
4. Find the Broadcast Address = 88.248.235.255

3.) 56.58.128.76 255.128.0.0

1. Find the Subnet = 56.0.0.0
2. Find the 1st Usable Host = 56.0.0.1
3. Find the Last Usable Host = 56.127.255.254
4. Find the Broadcast Address = 56.127.255.255

4.) 198.13.70.25 255.255.255.192

1. Find the Subnet = 198.13.70.0
2. Find the 1st Usable Host = 198.13.70.1
3. Find the Last Usable Host = 198.13.70.62
4. Find the Broadcast Address = 198.13.70.63

5.) 150.75.222.94 /18

1. Find the Subnet = 150.75.192.0
2. Find the 1st Usable Host = 150.75.192.1
3. Find the Last Usable Host = 150.75.255.254
4. Find the Broadcast Address = 150.75.255.255

6.) 198.134.190.70 /28

1. Find the Subnet = 198.134.190.64
2. Find the 1st Usable Host = 198.134.190.65
3. Find the Last Usable Host = 198.134.190.78
4. Find the Broadcast Address = 198.134.190.79


7.) 47.165.237.34 /21

1. Find the Subnet = 47.165.232.0
2. Find the 1st Usable Host = 47.165.232.1
3. Find the Last Usable Host = 47.165.239.254
4. Find the Broadcast Address = 47.165.239.255

8.) Is Ip address 79.246.255.1 with a subnet mask 255.224.0.0 a valid host ip address?

Yes. It falls in the 79.224.0.0 subnet and is a valid host ip address.

9.) 107.30.205.80 255.255.255.240

1. Find the Subnet = 107.30.205.80
2. Find the 1st Usable Host = 107.30.205.81
3. Find the Last Usable Host = 107.30.205.94
4. Find the Broadcast Address = 107.30.205.95

10.) Is 193.43.65.127 with a 255.255.255.192 mask a vaild Host IP address?

No. 193.43.65.127 is the broadcast address for the 193.43.65.64 subnet.

11.) 17.46.23.96 255.248.0.0

1. Find the Subnet = 17.40.0.0
2. Find the 1st Usable Host = 17.40.0.1
3. Find the Last Usable Host = 17.47.255.254
4. Find the Broadcast Address = 17.47.255.255

12.) 139.7.98.15 255.255.128.0

1. Find the Subnet = 139.7.0.0
2. Find the 1st Usable Host = 139.7.0.1
3. Find the Last Usable Host = 139.7.127.254
4. Find the Broadcast Address = 139.7.127.255

13.) 199.180.150.119 /26 can't communicate with 199.180.150.128 /26 what is the problem?

199.180.150.119 /26 is on the 199.180.150.0 subnet while 199.180.150.128 /26 is the subnet address for .128 subnet and is not a usable ip address.

1. Find the Subnet = 199.180.150.0
2. Find the 1st Usable Host = 199.180.150.1
3. Find the Last Usable Host = 199.180.150.126
4. Find the Broadcast Address = 199.180.150.127

1. Find the Subnet = 199.180.150.128
2. Find the 1st Usable Host = 199.180.150.129
3. Find the Last Usable Host = 199.180.150.254
4. Find the Broadcast Address = 199.180.150.255

14.) 205.39.228.185 255.255.255.224

1. Find the Subnet = 205.39.228.160
2. Find the 1st Usable Host = 205.39.228.161
3. Find the Last Usable Host = 205.39.228.190
4. Find the Broadcast Address = 205.39.228.191

15.) 15.19.11.2 /15

1. Find the Subnet = 15.18.0.0
2. Find the 1st Usable Host = 15.18.0.1
3. Find the Last Usable Host = 15.19.255.254
4. Find the Broadcast Address = 15.19.255.255

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